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Diagnostic ultrasound of frequency 4.50 MHz is used to examine tumors in soft tissue. What is the wavelength in air of such a sound wave?

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We can find the wavelength from the equation:

v=λf    λ=vf\begin{aligned} v=\lambda f \implies \lambda =\frac{v}{f} \end{aligned}

Substitute the given and we will get:

 λ=343 ms4.50106 Hz    λ=7.62105 m\begin{aligned} &~ \lambda=\frac{343\mathrm{~\frac{m}{s}}}{4.50\cdot 10^6\mathrm{~Hz}} \\ \implies &\boxed{ \lambda=7.62\cdot 10^{-5} \mathrm{~m}} \end{aligned}

Where we have used the known value of the speed of sound in air.

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