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A common technique for estimating animal populations is to tag and release individual animals in two different outings. This procedure is called catch and release. If the wildlife remain in the sampling area and are randomly caught, a fraction of the animals tagged during the first outing are likely to be caught again during the second outing. Based on the number tagged and the fraction caught twice, the total number of animals in the area can be estimated. a. Consider a case in which 200200 fish are tagged and released during the first outing. During a second outing in the same area, 200200 fish are again caught and released, of which one-half are already tagged. Estimate NN, the total number of fish in the entire sampling area. Explain your reasoning, b. Consider a case in which 200200 fish are tagged and released during the first outing. During a second outing in the same area, 200200 fish are again caught and released, of which one-fourth are already tagged. Estimate NN the total number of fish in the entire sampling area. Explain your reasoning. c. Generalize your results from parts (a) and (b) by letting pp be the fraction of tagged fish that are caught during the second outing. Find a formula for the function N=f(p)N=f(p) that relates the total number of fish, NN, to the fraction tagged during the second outing, pp. d. Graph the function obtained in part (c). What is the domain? Explain. e. Suppose that 15%15 \% of the fish in the second sample are tagged. Use the formula from part (c) to estimate the total number of fish in the sampling area. Confirm your result on your graph. f. Locate a real study in which the catch and release method was used. Report on the specific details of the study and describe how closely it followed the theory outlined in this problem.

Question

Direct measurements of the atmospheric carbon dioxide (CO2)\left(\mathrm{CO}_2\right) concentration have been made since about 19591959, when the measured concentration was about 316316 parts per million. In 20172017, the concentration was about 407407 parts per million. Assume that this growth can be modeled with an exponential function of the form Q=Q0×(1+r)tQ=Q_0 \times(1+r)^t. a. By experimenting with various values of the fractional growth rate rr, find an exponential function that fits the given data for 19591959 and 20172017. b. Use this exponential model to predict when the CO2\mathrm{CO}_2 concentration will be 560560 parts per million (twice its preindustrial level). c. Research recent trends in the carbon dioxide concentration. Does your model seem to fit, overestimate, or underestimate its recent rise? Explain.

Solution

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Answered 1 year ago
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(a)(a) As we are observing the change of concentration of carbon dioxide of 9191 part per million over the course of 5858 years, we are dealing with a relatively small growth rate. We can use a trial and error method on an equation

C=316(1+r)58C=316\left(1+r\right)^{58}

to determine the appropriate growth rate to get the concentration of C=407C=407

r=1%=0.01C=562.76r=0.5%=0.005C=422r=0.4%=0.004C=398.33r=0.45%=0.0045C=410r=0.44%=0.0044C=407.64r=0.43%=0.0043C=405.29r=0.437%=0.00437C=406.9\begin{align*} r&=1\%=0.01&\longrightarrow C&=562.76\\ r&=0.5\%=0.005&\longrightarrow C&=422\\ r&=0.4\%=0.004&\longrightarrow C&=398.33\\ r&=0.45\%=0.0045&\longrightarrow C&=410\\ r&=0.44\%=0.0044&\longrightarrow C&=407.64\\ r&=0.43\%=0.0043&\longrightarrow C&=405.29\\ r&=0.437\%=0.00437&\longrightarrow C&=406.9\\ \end{align*}

So, we can conclude that the approximate growth rate is r=0.437%r=0.437\%.

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