Question

Each of the slender rods of length l and mass m is welded to the circular disk which rotates about the vertical z-axis with an angular velocity ω\omega. Each rod makes an angle β\beta with the vertical and lies in a plane parallel to the y-z plane. Determine an expression for the angular momentum HOH_O of the two rods about the origin O of the axes.

Solution

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Answered 2 years ago
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Since the disk rotates about zz-axis at the rate ωz=ω  k\omega_z=\omega\;\textbf{k}, thus ωx=ωy=0\omega_x=\omega_y=0, referring to equation (7-11) the angular momentum of the two rods about the origin OO is

HO=(Ixz  ωz)  i(Iyz  ωz)  j+(Izz  ωz)  k\begin{align*} H_O&=(-I_{xz}\;\omega_z)\;\textbf{i}-(I_{yz}\;\omega_z)\;\textbf{j}+(I_{zz}\;\omega_z)\;\textbf{k}\tag{1}\\ \end{align*}

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