Related questions with answers
Either by hand or using a computer software package, sketch the phase plane diagrams for the given system. Discuss the stability of each limit cycle and critical point. Here and .
,
Solution
VerifiedMultiplying the first equation by , the second one by and adding, we get
Using the identity
we have
Simplify
We have that when . Thus, the origin () is not an isolated critical point. Note that () for or , and for .
Consequently, the trajectories spiral into the limit cycles (hence, stable) and away from the limit cycles (hence, unstable). {\bf The origin is a stable critical point}. To realize this, notice that for every there exists a positive integer such that , so we can simply choose . Then, the fact that is a stable limit cycle guarantees that any trajectory that begins within of the origin remains within of the origin.
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