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Question

Estimate the moment of inertia of a bicycle wheel 67 cm67 \mathrm{~cm} in diameter. The rim and tire have a combined mass of 1.1 kg1.1 \mathrm{~kg}. The mass of the hub (at the center) can be ignored (why?).

Solution

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Moment of inertia of a wheel can be calculated:

I=mr2=1.1(0.672)2I=m\cdot r^2=1.1 \cdot \left (\frac{0.67}{2} \right )^2

I=0.1234kgm2\boxed{I=0.1234\,\,\rm{kgm^2}}

We can ignore mass at the center because its effects are negligible due to the small distance from the centre\textbf{small distance from the centre}.

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