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Question

Ethane (C2H6)(C_2H_6) gas at 77F,77^\circ F, 1 atm enters a well-insulated reactor operating at steady state and burns completely with air entering at 240F,240^\circ F, 1 atm. Determine the temperature of the products, in F.^\circ F. Neglect kinetic and potential energy effects.

Solution

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Answered 2 years ago
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The ratio of NX2\ce{N2} to OX2\ce{O2} in air is,

nNX2nOX2=0.790.21=3.76\begin{align*} \dfrac{n_{\ce{N2}}}{n_{\ce{O2}}} &= \dfrac{0.79}{0.21} \\ &= 3.76 \end{align*}

The chemical reaction is,

CX2HX6+x(OX2+3.76NX2)aCOX2+bHX2O+3.76xNX2\ce{C2H6 + x(O2 + 3.76 N2) -> a CO2 + b H2O + 3.76x N2}

The mass balance of C is:

2=a\begin{align*} 2 &= a \end{align*}

The mass balance of H is:

6=2b3=b\begin{align*} 6 &= 2b \\ 3 &= b \end{align*}

The mass balance of O is:

2x=2a+b2x=4+3x=3.5\begin{align*} 2x &= 2a + b \\ 2x &= 4 + 3 \\ x &= 3.5 \end{align*}

Substitute in the chemical reaction,

CX2HX6+3.5OX2+13.16NX22COX2+3HX2O+13.16NX2\ce{C2H6 + 3.5 O2 + 13.16 N2 -> 2 CO2 + 3 H2O + 13.16 N2}

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