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Evaluate 2x34(3xyz2)2 x^3-4\left(3 x y-z^2\right) for x=2,y=3x=-2, y=3, and z=4z=-4.

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2x34(3xyz2)2x^3-4(3xy-z^2)

Substitute x=2,y=3,x=-2,y=3, and z=4z=-4.

=2(2)34[3(2)(3)(4)2]=2(-2)^3-4[3(-2)(3)-(-4)^2]

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