Question

Evaluate $2 x^3-4\left(3 x y-z^2\right)$ for $x=-2, y=3$, and $z=-4$.

Solutions

VerifiedSolution A

Solution B

Answered 2 years ago

Step 1

1 of 7$2x^3-4(3xy-z^2)$

Substitute $x=-2,y=3,$ and $z=-4$.

$=2(-2)^3-4[3(-2)(3)-(-4)^2]$

Step 1

1 of 2$\begin{align*} 2(-2)^{3}-4(3(-2)(3)-(-4)^{2}) &=2(-8)-4(-18-16)\\ &=-16-4(-34)\\ &=-16+136\\ &=120 \end{align*}$

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