Try the fastest way to create flashcards

Evaluate each expression if p=4,q=8p=-4, q=8, and r=10r=-10. See the mentioned example.

(p+2)23r2q\dfrac{-(p+2)^2-3 r}{2-q}


Answered 2 years ago
Answered 2 years ago
Step 1
1 of 2

Given that p=4p=-4, q=8q=8, and r=10r=-10, we can evaluate the expression (p+2)23r2q-\frac{-(p+2)^2-3r}{2-q} as follows:

(p+2)23r2q=(4+2)23(10)28Substitute p=4q=8, and r=10=(2)23(10)28Add terms inside parentheses=(4)3(10)28Evaluate the exponential=4+3028Simplify=266Add/Subtract=133Simplify\begin{aligned} \frac{-(p+2)^2-3r}{2-q}&=\frac{-(-4+2)^2-3(-10)}{2-8} &&\text{Substitute $p= - 4$, $q= 8$, and $r= -10$}\\ &=\frac{-(-2)^2-3(-10)}{2-8} &&\text{Add terms inside parentheses}\\ &=\frac{-(4)-3(-10)}{2-8} &&\text{Evaluate the exponential}\\ &=\frac{-4+30}{2-8} &&\text{Simplify}\\ &=\frac{26}{-6} &&\text{Add/Subtract}\\ &=-\frac{13}{3} &&\text{Simplify}\\ \end{aligned}

Create a free account to view solutions

Create a free account to view solutions

Recommended textbook solutions

Precalculus 2nd Edition by Carter, Cuevas, Day, Malloy


2nd EditionISBN: 9780076602186Carter, Cuevas, Day, Malloy
8,886 solutions
Nelson Functions 11 1st Edition by Chris Kirkpatrick, Marian Small

Nelson Functions 11

1st EditionISBN: 9780176332037Chris Kirkpatrick, Marian Small
1,275 solutions
Precalculus 3rd Edition by David I. Schneider, Hornsby, Lial


3rd EditionISBN: 9780321227621David I. Schneider, Hornsby, Lial
8,326 solutions
Precalculus with Limits 3rd Edition by Larson

Precalculus with Limits

3rd EditionISBN: 9781133962885 (3 more)Larson
11,068 solutions

More related questions