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Question

Evaluate each of the following in x+iyx + iy form, and compare with a computer solution. ln(i)\ln (-i)

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Answered 2 years ago
Answered 2 years ago
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Find :\textbf{\textcolor{#c34632}{Find :}} w=ln(i)w=\ln(-i)

Let's assume z=iz=-i so the polar form of the number is

z=rexp(iθ)              (1)z=r\exp(i\theta)\;\;\;\;\;\;\;\Rightarrow(1)

The absolute rr is given by

r=i=1              (2)\boxed{r=|-i|=1}\;\;\;\;\;\;\;\Rightarrow(2)

And the angle θ\theta is given by

θ=3π2\boxed{\theta=\dfrac{3\pi}{2}}

Because the number locates in negative imaginary axis . so the number is

z=exp(3πi/2)\boxed{z=\exp(3\pi i/2)}

So the the number ww is

w=ln(rexp(θi))=ln(r)+(3π/2+2nπ)i                n=0,±1,±2,±3,=ln(1)+(3π/2+2nπ)i                n=0,±1,±2,±3,=(3π/2+2nπ)i                n=0,±1,±2,±3,\begin{align*} w=&\ln(r\exp(\theta i))\\ =&\ln(r)+(3\pi/2+2n\pi)i \;\;\;\;\;\;\;\;n=0,\pm 1 ,\pm 2 ,\pm 3 ,\dots\\ =&\ln(1) +(3\pi /2+2n\pi)i\;\;\;\;\;\;\;\;n=0,\pm 1 ,\pm 2 ,\pm 3 ,\dots\\ =&\boxed{(3\pi/2+2n\pi)i}\;\;\;\;\;\;\;\;n=0,\pm 1 ,\pm 2 ,\pm 3 ,\dots\\ \end{align*}

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