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Evaluate Cf(r)ds\int_C f(\mathbf{r}) d s with ff and CC as follows. (Show the details.) f=2+x2+3y2,C:r=[t,t,t2],0t3f=\sqrt{2+x^2+3 y^2}, \quad C: \mathbf{r}=\left[t, t, t^2\right], 0 \leqq t \leqq 3.

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Answered 2 years ago
Answered 2 years ago
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Given:

F=2+x2+3y2F=\sqrt{2+x^2+3y^2}

As C:r=[t,t,t2]C:r=[ t, t, t^2], therefore:

x=ty=tz=t2\begin{align*} x&= t\\ y&= t\\ z&=t^2\\ \end{align*}

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