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Question

Evaluate the function at the indicated values.

f(x)=x3+2x;f(2),f(1),f(0),f(12)f ( x ) = x ^ { 3 } + 2 x ; \quad f ( - 2 ) , f ( - 1 ) , f ( 0 ) , f \left( \frac { 1 } { 2 } \right)

Solution

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Step 1
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Since f(x)=x3+2xf(x) = x^3 + 2x,

f(2)=(2)3+2(2)=84=12f(-2) = (-2)^3 + 2(-2) = -8 - 4 = -12,

f(1)=(1)3+2(1)=1+2=3f(1) = (1)^3 + 2(1) = 1 +2 =3,

f(0)=(0)3+2(0)=0+0=0f(0) = (0)^3 + 2(0) = 0 +0 =0,

f(13)=(13)3+2(13)=127+23=127+1827=1927f(\frac{1}{3}) = (\frac{1}{3})^3 + 2(\frac{1}{3}) = \frac{1}{27} +\frac{2}{3} =\frac{1}{27} +\frac{18}{27} = \frac{19}{27}, and

f(0.2)=(0.2)3+2(0.2)=0.008+0.4=0.408f(0.2) = (0.2)^3 + 2(0.2) = 0.008 +0.4 =0.408.

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