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Question

Express the complex number  33i \space \sqrt{3}-3i\space, in the polar form.

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Rectangular coordinated of the complex number 33i\sqrt{3}-3i are x=3x=\sqrt{3} and y=3y=-3. Calculate the magnitude by using the formula r=x2+y2r=\sqrt{x^2+y^2}.

r=32+(3)2=3+9=12=23\begin{align*} r&=\sqrt{\sqrt{3}^2+(-3)^2}=\sqrt{3+9}=\sqrt{12}=2\sqrt{3} \end{align*}

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