## Related questions with answers

Question

Factor each polynomial using the difference-of-squares pattern. $x ^ { 4 } - 1$

Solution

VerifiedStep 1

1 of 2$x^4-1= (x^2)^2-1^2$

$\text{\color{#c34632}Recall that: $A^2-B^2 = (A+B)(A-B)$}$

$(x^2)^2-1^2 = (x^2+1)(x^2-1)$

$\text{\color{#4257b2}Again, use the same formula: $A^2-B^2 = (A+B)(A-B)$}$

$(x^2+1){\color{#4257b2}(x^2-1^2)} =(x^2+1){\color{#4257b2}(x+1)(x-1)}$

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