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Question

Factor each polynomial using the difference-of-squares pattern. x41x ^ { 4 } - 1

Solution

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x41=(x2)212x^4-1= (x^2)^2-1^2

Recall that: A2B2=(A+B)(AB)\text{\color{#c34632}Recall that: $A^2-B^2 = (A+B)(A-B)$}

(x2)212=(x2+1)(x21)(x^2)^2-1^2 = (x^2+1)(x^2-1)

Again, use the same formula: A2B2=(A+B)(AB)\text{\color{#4257b2}Again, use the same formula: $A^2-B^2 = (A+B)(A-B)$}

(x2+1)(x212)=(x2+1)(x+1)(x1)(x^2+1){\color{#4257b2}(x^2-1^2)} =(x^2+1){\color{#4257b2}(x+1)(x-1)}

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