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Question

Factor the sum or difference of cubes. Factor out the GCF first.

2x6+54x32 x ^ { 6 } + 54 x ^ { 3 }

Solution

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Answered 2 years ago
Answered 2 years ago
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Here we have;

2x6+54x3factor out 2x3=2x3(x3+27)we can rewrite this as;=2x3(x3+(3)3)factor by applying a3+b3=(a+b)(a2ab+b2)=2x3(x+3)(x23x+9)\begin{aligned} &2x^6+54x^3&&\color{#19804f}\text{factor out $2x^3$}\\ &=2x^3(x^3+27)&&\color{#19804f}\text{we can rewrite this as;}\\ &=2x^3(x^3+(3)^3)&&\color{#19804f}\text{factor by applying $a^3+b^3=(a+b)(a^2-ab+b^2)$}\\ &=\color{#c34632}2x^3(x+3)(x^2-3x+9) \end{aligned}

Therefore, we now have 2x3(x+3)(x23x+9)\color{#c34632}\boxed{2x^3(x+3)(x^2-3x+9)}

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