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Question
Find a logic statement involving p and q that generates each of the following truth tables .
Solution
VerifiedStep 1
1 of 2Guided by the fact that only the conjunction is true, we seek out rows where the last entry is true.
We find three such rows, and only one yields F (false), so we change the focus of our search.
We find that combination (that yields false) and invert it.
"" is false for ( p is true) and (q is false) so,
( p) and not(q) will yield a false value.
Inverting, by DeMorgan's Law, the statement ( p) and not(q), we have
"" ... apply DeMorgan's Law
"" $=(\sim p)\vee[\sim(\sim q)]=\sim p\vee q.
$
Check the truth values, row by row, and note the results: T,F,T,T, as they should be.
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