## Related questions with answers

Question

Find all values of x satisfying the given conditions.

$\left. \begin{array} { l } { y _ { 1 } = 10 ( 2 x - 1 ) , y _ { 2 } = 2 x + 1 , \text { and } y _ { 1 } \text { is } 14 \text { more than } 8 \text { times } y _ { 2 } . } \end{array} \right.$

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 4Two equations $y_1$ and $y_2$ are given, and also $y_{1}$ is $14$ more than $8$ times $y_{2}$. So our equation will be:

$10(2x-1) = 14 + 8(2x+1)$

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