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Question

Find all values of x satisfying the given conditions.

y1=10(2x1),y2=2x+1, and y1 is 14 more than 8 times y2.\left. \begin{array} { l } { y _ { 1 } = 10 ( 2 x - 1 ) , y _ { 2 } = 2 x + 1 , \text { and } y _ { 1 } \text { is } 14 \text { more than } 8 \text { times } y _ { 2 } . } \end{array} \right.

Solution

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Answered 1 year ago
Answered 1 year ago
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Two equations y1y_1​ and y2y_2​ are given, and also y1y_{1} is 1414 more than 88 times y2y_{2}. So our equation will be:

10(2x1)=14+8(2x+1)10(2x-1) = 14 + 8(2x+1)

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