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Question

Find an equation of the circle that satisfies the stated conditions.

Tangent to both axes, center in the second quadrant, radius 44

Solution

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Answered 1 year ago
Answered 1 year ago
Step 1
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To find an equation to a circle, follow the steps below

  1. determine the center (C)(C) of a circle and the value of the radius (r)(r)
  2. substitute the values to the equation

(xh)2+(yk)2=r2(x-h)^2+(y-k)^2=r^2

Note that when the center (C)(C) is (0,0)(0,0), we reduce the equation to

x2+y2=r2x^2+y^2=r^2

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