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Question

Find an equation of the tangent line to the circle at the indicated point. Recall from geometry that the tangent line to a circle is perpendicular to the radius of the circle at the point of tangency. Circle x2+y2=12x^{2}+y^{2}=12 Point (2,22)(2,-2 \sqrt{2})

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For the circle x2+y2=12x^2+y^2=12 we need to find a tangent line at the point (2,22)(2,-2\sqrt2).

Center of the circle : (0,0)\color{#4257b2}(0,0).

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