## Related questions with answers

Question

Find an equation of the tangent line to the circle at the indicated point. Recall from geometry that the tangent line to a circle is perpendicular to the radius of the circle at the point of tangency. Circle $x^{2}+y^{2}=12$ Point $(2,-2 \sqrt{2})$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 6For the circle $x^2+y^2=12$ we need to find a tangent line at the point $(2,-2\sqrt2)$.

Center of the circle : $\color{#4257b2}(0,0)$.

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create a free account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### Principles of Mathematics 10

1st Edition•ISBN: 9780070973329Brian McCudden, Chris Dearling, Wayne Erdman1,429 solutions

#### Algebra and Trigonometry: Structure and Method, Book 2

1st Edition•ISBN: 9780395977255 (1 more)Brown, Dolciani, Kane, Sorgenfrey8,447 solutions

#### Precalculus with Limits: A Graphing Approach

6th Edition•ISBN: 9781111427641 (2 more)Larson9,073 solutions

#### Cambridge IGCSE Mathematics: Core and Extended

3rd Edition•ISBN: 9781444191707Ric Pimentel1,773 solutions

## More related questions

1/4

1/7