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Question

**Find an equation of the tangent line to the graph at the given point.**

Rotated ellipse: $7x^2-6\sqrt{3}xy+13y^2-16=0$ Point: $\left(\sqrt{3},1\right)$

Solution

VerifiedAnswered 1 year ago

Answered 1 year ago

Step 1

1 of 7To find an equation of the tangent line to the graph at $(\sqrt{3},1)$ we must find a slope of a tangent line and then using the point-slope form we can write the equation of a tangent line.

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