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Question

Find an equation of the tangent line to the graph of the function at the given point.

FunctionPointy=tan x(π4,1)\begin{matrix} \text{Function} & \text{Point}\\ \text{y=tan x} & \text{}{\left(-\frac{\pi}{4},-1\right)}\\ \end{matrix}

Solution

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Use differentiation rules and the derivatives of the basic trigonometric functions to find the derivative of the given function.

y=tan(x)y=ddx[tan(x)]=sec2(x)\begin{align*} y&=\tan(x)\\ y'&=\dfrac{d}{dx}\qty[\tan(x)]\\ &={\color{#4257b2}\sec^2(x)}\\ \end{align*}

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