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Question

Find dy/dxdy/dx and d2y/dx2d^2y/dx^2, and find the slope and concavity (if possible) at the given value of the parameter.

Parametric Equation\underline{Parametric\ Equation}

x=t, y=3t1x=\sqrt t,\ y=3t-1

Point\underline{Point}

t=1t=1

Solution

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Answered 2 years ago
Answered 2 years ago
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Given:

x=ty=3t1\begin{aligned} x&=\sqrt{t} \\ y&=3t-1 \end{aligned}

We need to determine the derivatives dydx\frac{dy}{dx} and d2ydx2\frac{d^2y}{dx^2}, while also determining the slope and concavity at t=1t=1.

The following formula can be used to determine the derivative dydx\frac{dy}{dx} of parametric equations:

dydx=dy/dtdx/dt\begin{aligned} \frac{dy}{dx}&=\frac{dy/dt}{dx/dt} \end{aligned}

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