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Question

Find equations for the tangent plane and normal line to the surface given at the prescribed point.

x3+2xy27x3+3y+1=0 at P0(1,1,1)x^{3}+2 x y^{2}-7 x^{3}+3 y+1={0} \text { at } P_{0}(1,1,1)

Solution

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Answered 2 years ago
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We have to find the equation of the tangent plane and normal line to the curve

x3+2xy27x3+3y+1=0,x^3+2xy^2-7x^3+3y+1=0,

at P0(1,1,1)P_0(1,1,1). Let F(x,y)=x3+2xy27x3+3y+1F(x,y)=x^3+2xy^2-7x^3+3y+1, and consider CC to be the level curve F(x,y)=0F(x,y)=0. The gradient F\nabla F is normal to CC at P0P_0. First we find the gradient of FF which is

F(x,y)=Fx(x,y)i+Fy(x,y)j.\nabla F(x,y)=F_x(x,y)\textbf{i}+F_y(x,y)\textbf{j}.

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