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Question

Find

sinθ2,cosθ2, and tanθ2\sin \frac { \theta } { 2 } , \cos \frac { \theta } { 2 } , \text { and } \tan \frac { \theta } { 2 }

for the set of conditions.

sinθ=2425 and 180<θ<270\sin \theta = - \frac { 24 } { 25 } \text { and } 180 ^ { \circ } < \theta < 270 ^ { \circ }

Solution

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Answered 2 years ago
Answered 2 years ago
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Since 180°<θ<270°, we can write cosθ=1sin2θ\text{\color{#c34632}Since $180\text{\textdegree}<\theta<270\text{\textdegree}$, we can write $\cos\theta = -\sqrt{1-\sin^2\theta}$}

cosθ=1(2425)2\cos\theta = -\sqrt{1-\left( -\dfrac{24}{25}\right)^2}

cosθ=1242252\cos\theta = -\sqrt{1-\dfrac{24^2}{25^2}}

cosθ=252242252\cos\theta = -\sqrt{\dfrac{25^2-24^2}{25^2}}

cosθ=(2524)(25+24)252\cos\theta = -\sqrt{\dfrac{\left( 25-24\right)\left(25+24 \right)}{25^2}}

cosθ=(1)(49)252\cos\theta = -\sqrt{\dfrac{\left( 1\right)\left(49 \right)}{25^2}}

cosθ=49252\cos\theta = -\sqrt{\dfrac{49}{25^2}}

cosθ=49252\cos\theta = -\dfrac{\sqrt{49}}{\sqrt{25^2}}

cosθ=725\cos\theta = -\dfrac{7}{25}

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