Try the fastest way to create flashcards
Question

# Find the angle of elevation to the top of the 1250 -ft Empire State Building from a point 850ft from the base.

Solution

Verified
Step 1
1 of 2

Height of the Empire State Building is 1250-ft and the distance of Empire State Building form its base is 850 ft. So the height of Empire State Building will be opposite side length and horizontal distance of Empire State Building will be adjacent side. So to find angle of elevation we will use $\tan \theta$

\begin{align*} \tan \theta&=\dfrac{\text{Height of the Empire State Building}}{\text{Distance of Empire State Building from its base}}\\ \\ \tan \theta&=\dfrac{1250}{850}=0.532\tag{Putting value}\\ \\ \theta&=\tan^{-1}\left(1.470\right)\tag{Simplifying}\\ \\ \theta&\approx56\text{\textdegree} \tag{\tan 56\text{\textdegree}\approx0.1.470}\\ \end{align*}

$\textbf{Hence, angle of elevation of the Empire State Building is 56\text{\textdegree}}$

## Recommended textbook solutions

#### Tennessee Bridge Math

1st EditionISBN: 9780076611294Chicha Lynch, Eugene Olmstead
8,789 solutions

#### enVision Algebra 1

1st EditionISBN: 9780328931576Al Cuoco, Christine D. Thomas, Danielle Kennedy, Eric Milou, Rose Mary Zbiek
3,653 solutions

#### Algebra 1

4th EditionISBN: 9781602773011Saxon
5,377 solutions

#### Big Ideas Math Integrated Mathematics II

1st EditionISBN: 9781680330687Boswell, Larson
4,539 solutions