## Related questions with answers

Find the angle of elevation to the top of the 1250 -ft Empire State Building from a point 850ft from the base.

Solution

VerifiedHeight of the Empire State Building is 1250-ft and the distance of Empire State Building form its base is 850 ft. So the height of Empire State Building will be opposite side length and horizontal distance of Empire State Building will be adjacent side. So to find angle of elevation we will use $\tan \theta$

$\begin{align*} \tan \theta&=\dfrac{\text{Height of the Empire State Building}}{\text{Distance of Empire State Building from its base}}\\ \\ \tan \theta&=\dfrac{1250}{850}=0.532\tag{Putting value}\\ \\ \theta&=\tan^{-1}\left(1.470\right)\tag{Simplifying}\\ \\ \theta&\approx56\text{\textdegree} \tag{$\tan 56\text{\textdegree}\approx0.1.470$}\\ \end{align*}$

$\textbf{Hence, angle of elevation of the Empire State Building is $56\text{\textdegree}$}$

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