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Question

Find the coordinates xˉ,yˉ\bar{x}, \bar{y} of the center of gravity of a mass of density f(x,y)=1f(x, y)=1 in a region RR, where RR is the region x2+y2a2x^2+y^2 \leqq a^2 in the first quadrant. Check the result using polar coordinates.

Solution

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Answered 2 years ago
Answered 2 years ago
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Given:

z=1z=1

Region is x2+y2a2x^2+y^2\le a^2, x0x\ge 0 and y0y \ge 0

In polar coordinates:

x=rcosθx=r\cos \theta

y=rsinθy=r\sin\theta

Region is r2cos2θ+r2sin2θa2rar^2\cos^2 \theta+r^2 \sin^2 \theta \le a^2 \Rightarrow r \le a

as the region is first quadrant, 0θπ20 \le \theta \le \dfrac{\pi}{2}

Below is graph of region RR:

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