Question

Find the coordinates of the vertices and foci and the equations of the asymptotes for the hyperbola with the given equation. Then graph the hyperbola.

y216x225=1\frac{y^2}{16}-\frac{x^2}{25}=1

Solution

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Answered 2 years ago
Answered 2 years ago
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From the given equation,

y216x225=1\begin{aligned} \frac{y^2}{16}-\frac{x^2}{25}=1 \end{aligned}

We can conclude that the center is at the origin (0,0)(0,0), a2=16a^2=16, b2=25b^2=25, and the transverse axis is vertical.

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