## Related questions with answers

Question

Find the coordinates of the vertices and foci and the equations of the asymptotes for the hyperbola with the given equation. Then graph the hyperbola.

$\frac{y^2}{16}-\frac{x^2}{25}=1$

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 5From the given equation,

$\begin{aligned} \frac{y^2}{16}-\frac{x^2}{25}=1 \end{aligned}$

We can conclude that the center is at the origin $(0,0)$, $a^2=16$, $b^2=25$, and the transverse axis is vertical.

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