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Question

Find the curvature at the given point on the polar curve given.

r=12sinθ, where θ=π4r=1-2 \sin \theta, \text { where } \theta=\frac{\pi}{4}

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Let us consider the equation of the polar curve   r=12sinθ.~~r=1-2\sin \theta. We will now evaluate the curvature of the plane curve at   θ=π4.~~\theta=\dfrac{\pi}{4}. Now from above given context, we have

κ=r2+2r2rr(r2+r2)3/2,\kappa = \frac{|r^2+2r'^2-rr''|}{(r^2+r'^2)^{3/2}},

where   κ  ~~\kappa~~ denotes the curvature of the curve   r=12sinθ.~~r=1-2\sin \theta.

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