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Question

Find the distance between each pair of points. If necessary, round answers to two decimal places. (-2, 3) and (3, -9)

Solution

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Let x1=2 , x2=3x_{1}=-2 \ , \ x_{2}=3      and y1=3 , y2=9y_{1}=3 \ , \ y_{2}=-9

d=(x2x1)2+(y2y1)2d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}      Thedistanceform\quad {\color{#4257b2}The distance form}

d=(3(2))2+(93)2d=\sqrt{(3-(-2))^{2}+(-9-3)^{2}}      Substitutethegivenvalues\quad {\color{#4257b2}Substitute the given values}

d=(5)2+(12)2d=\sqrt{(5)^{2}+(-12)^{2}}      3(2)=5 and93=12\quad {\color{#4257b2} 3-(-2)=5 \ and -9-3=-12}

d=25+144d=\sqrt{25+144}      $\quad {\color{#4257b2} 52=255^{2}=25 \ and (12)2=144(-12)^{2}=144}$

d=169d=\sqrt{169}

=13 length unit

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