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Question

Find the eigenvalues of the matrix. For the eigenvalue, find an eigenvalue. Sketch the Gershgorin circles, and then locate the eigenvalues in these circles.

(2100100100000000)\left( \begin{array}{rrrr}{-2} & {1} & {0} & {0} \\ {1} & {0} & {0} & {1} \\ {0} & {0} & {0} & {0} \\ {0} & {0} & {0} & {0}\end{array}\right)

Solution

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For given matrix

A=(2100100100000000)A=\left(\begin{array}{cccc} -2 & 1 & 0 & 0\\ 1 & 0 & 0 & 1\\ 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 0 \end{array}\right)

the characteristic polynomial is:

pA(λ)=λI4A=λ+21001λ0100λ0000λ=λ2(λ(λ+2)1)=λ2(λ2+2λ1).p_A(\lambda)=|\lambda\boldsymbol{I_4}-\boldsymbol{A}|=\left|\begin{array}{cccc} \lambda+2 & -1 & 0 & 0\\ -1 & \lambda & 0 & -1\\ 0 & 0 & \lambda & 0\\ 0 & 0 & 0 & \lambda \end{array}\right|=\lambda^2(\lambda(\lambda+2)-1)=\lambda^2(\lambda^2+2\lambda-1).

Its roots (the eigenvalues of the matrix AA) are λ1=λ2=0,  λ3=1+2\color{#c34632}\lambda_1=\lambda_2=0,\;\lambda_3=-1+\sqrt{2} and λ4=12\color{#c34632}\lambda_4=-1-\sqrt{2}.

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