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Question

# Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.$\sin F$

Solution

Verified
Step 1
1 of 2

Recall that:

$\sin\theta=\dfrac{\text{length of the side {\color{#c34632}\bf{}opposite} to the angle \theta}}{\text{length of the {\color{#c34632}\bf{}hypotenuse}}}$

Use the given figure to substitute the lengths of

${\color{#c34632}\bf{}opposite side}$

and

${\color{#c34632}\bf{}hypotenuse}$

.

$\sin F=\dfrac{DE}{DF}=\dfrac{4}{5}$

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