## Related questions with answers

Question

Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.

$\sin F$

Solution

VerifiedStep 1

1 of 2Recall that:

$\sin\theta=\dfrac{\text{length of the side {\color{#c34632}\bf{}opposite} to the angle $\theta$}}{\text{length of the {\color{#c34632}\bf{}hypotenuse}}}$

Use the given figure to substitute the lengths of

${\color{#c34632}\bf{}opposite side}$

and

${\color{#c34632}\bf{}hypotenuse}$

.

$\sin F=\dfrac{DE}{DF}=\dfrac{4}{5}$

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### enVision Algebra 1

1st Edition•ISBN: 9780328931576Al Cuoco, Christine D. Thomas, Danielle Kennedy, Eric Milou, Rose Mary Zbiek3,245 solutions

#### Big Ideas Math Integrated Mathematics II

1st Edition•ISBN: 9781680330687Boswell, Larson4,539 solutions

## More related questions

- algebra

1/4

- algebra

1/7