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Question

Find the following ratio DEF\triangle D E F where mEm \angle E = 9090^\circ DE = 4, EF= 3, DF = 5.

sinF\sin F

Solution

Verified
Step 1
1 of 2

Recall that:

sinθ=length of the side opposite to the angle θlength of the hypotenuse\sin\theta=\dfrac{\text{length of the side {\color{#c34632}\bf{}opposite} to the angle $\theta$}}{\text{length of the {\color{#c34632}\bf{}hypotenuse}}}

Use the given figure to substitute the lengths of

oppositeside{\color{#c34632}\bf{}opposite side}

and

hypotenuse{\color{#c34632}\bf{}hypotenuse}

.

sinF=DEDF=45\sin F=\dfrac{DE}{DF}=\dfrac{4}{5}

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