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Question

Find the following ratio $\triangle D E F$ where $m \angle E$ = $90^\circ$ DE = 4, EF= 3, DF = 5.$\tan D$

Solution

Verified
Step 1
1 of 2

Recall that:

$\tan\theta=\dfrac{\text{length of the side {\color{#c34632}\bf{}opposite} to the angle \theta}}{\text{length of the side {\color{#c34632}\bf{}adjacent} to the angle \theta}}$

Use the given figure to substitute values for the

${\color{#c34632}\bf{}opposite}$

and the

${\color{#c34632}\bf{}adjacent}$

side lengths.

$\tan D=\dfrac{FE}{DE}=\dfrac{3}{4}$

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