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Question

Find the GCF of each group of monomials. x²y³ and

x³y5x³y^5

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x2y3=x2×y3x3y5=x2×x×y3×b×y2\begin{align*} &x^2y^3=x^2\times y^3 \\ &x^3y^5=x^2\times x \times y^3 \times b\times y^2 \end{align*}

So the GCF is x2y3x^2y^3

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