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Question

Find the general indefinite integral. ∫ sec t (sec t + tan t) dt

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I=sect(sect+tant)dtI=\displaystyle \int \sec t(\sec t +\tan t)dt

=(sec2t+secttant)dt=\displaystyle \int (\sec^2 t +\sec t\tan t)dt

We know that (sec2t)dt=tant+c\int( \sec^2 t )dt=\tan t +c

And also (secttant)dt=sect+c\int (\sec t\tan t)dt=\sec t+c

I=tant+sect+cI=\tan t+\sec t+c

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