Question

Find the general solutions of the differential equations. 2d2ydt2+5dydt+2y=02 \frac{d^{2} y}{d t^{2}}+5 \frac{d y}{d t}+2 y=0

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Given

2d2ydt2+5dydt+2y=02\dfrac{d^2y}{dt^2}+5\dfrac{dy}{dt}+2y=0

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