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Question

Find the indefinite integral. (Check by differentiation.)

1y23y dy\displaystyle{\int}\frac{1-y^{2}}{3y}\ dy

Solution

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Answered 2 years ago
Answered 2 years ago
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The task is to compute for the indefinite integral of the function

f(y)=1y23y=13yy3=13(1yy)\begin{aligned} f(y)= \frac{1-y^{2}}{3y}= \frac{1}{3y}- \frac{y}{3}= \frac{1}{3} \left(\frac{1}{y}-y\right) \end{aligned}

and by differentiation, check the validity of the solution.

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