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Question

Find the interval [μzσn,μ+zσn]\left[\mu-z \frac{\sigma}{\sqrt{n}}, \mu+z \frac{\sigma}{\sqrt{n}}\right] within which 9595 percent of the sample means would be expected to fall, assuming that each sample is from a normal population.

μ=1,000,σ=15,n=9\mu=1,000, \sigma=15, n=9

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Answered 1 year ago
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To determine the interval with 95%95\% of the sample mean and known standard deviation. Let's start by defining a confidence interval for the mean of the population. But first and foremost, we must select the most acceptable formula for our objectives. For situations where the standard deviation is known, we can use the following formula.

μ±zα2σn\begin{aligned} \mu \pm z_\frac{\alpha}{2} \frac{\sigma}{\sqrt{n}} \end{aligned}

where,

  • nn - is the sample size,
  • zα2z_{\frac{\alpha}{2}} - is the appropriate zz-value from the standard normal distribution table corresponding to level of significance,
  • μ\mu - is the population mean,
  • σ\sigma - is the population standard deviation.

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