## Related questions with answers

Question

Find the linearization L(x) of ƒ(x) at x = a. ƒ(x) = tan x, a = π

Solutions

VerifiedSolution A

Solution B

Solution C

Answered 2 years ago

Step 1

1 of 3To find the required linearization, we need to find $f'(\pi)$, where $f(x)=\tan x$

$f'(x)=\dfrac{d\left(\tan x\right)}{dx}$

Remember that: the derivative of $\tan x$ is $\sec^2x$

$f'(x)=\sec^2x$

Substitute $x=\pi$

$f'(\pi)=\sec^2\pi$

$f'(\pi)=(-1)^2=1$

Answered 2 years ago

Step 1

1 of 3We know

$L(x)=f(a)+f'(a)(x-a)$

and

$f(x)\approx L(x), \quad x\approx a$

Answered 2 years ago

Step 1

1 of 4$f(\pi) = 0\\ f'(\pi) = sec^2(\pi) = 1$

calculate the values needed for the linearization equation

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