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Question

# Find the momentum, kinetic energy, and total energy of an electron with speed (c) $0.50 c$.

Solution

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For a particle of mass $m$ moving at relativistic speed $v$, the momentum $p$, kinetic energy $K$ and total relativistic energy $E$ is

\begin{align} p &= \gamma mv \\ K &= (\gamma - 1)mc^2 \\ E &= \gamma mc^2 \end{align}

where $\gamma = \dfrac{1}{\sqrt{1 - \dfrac{v^2}{c^2}}}$ is the Lorentz factor

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