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Question

Find the parametric equations of the line that is tangent to the curve of intersection of the surfaces x=z2x=z^2 and y=z3y=z^3 at (1,1,1).

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Answered 2 years ago
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Given f(x,y,z)=xz2=0f\left(x,y,z \right)=x-z^{2}=0 and g(x,y,z)=yz3=0g\left(x,y,z\right)=y-z^{3}=0

f(x,y,z)=f(x,y,z)xi^+f(x,y,z)yj^+f(x,y,z)zk^=i^2zk^f(1,1,1)=1i^2k^\begin{align*} \nabla f\left(x,y,z \right)&=\dfrac{\partial f\left(x,y,z \right)}{\partial x}\hat{i}+\dfrac{\partial f\left(x,y,z \right)}{\partial y}\hat{j}+\dfrac{\partial f\left(x,y,z \right)}{\partial z}\hat{k} \\ &=\hat{i} -2z\hat{k} \\ \nabla f\left(1,1,1 \right)&=1\hat{i} -2\hat{k}\end{align*}

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