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Question

Find the products ABAB and BABA for the diagonal matrices.

A=A=

[300050000]\begin{bmatrix} 3&0&0\\ 0&-5&0\\ 0&0&0 \end{bmatrix}

B=B=

[7000400012]\begin{bmatrix} -7&0 &0\\ 0&4 &0 \\ 0&0 &12 \end{bmatrix}

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Before carrying out any product between matrices (AB)(AB), it is vital to check that it is defined.

Remember that for the product of two matrices to be defined, the column number of the first matrix (the matrix that is furthest to the left) has to be equal to the row number of the second matrix. If AA is an m×km\times k matrix and BB is k×nk \times n, then the product of ABAB gives us an m×nm\times n matrix CC.

Note that each element cijc_{ij} of the resulting matrix CC is the sum of the products of each element of a row ii of AA with its corresponding element of column jj of BB. This is

cij=p=1kaipbpj(1)\textcolor{#4257B2}{c_{ij} =\sum_{p=1}^{k} a_{i p} b_{p j}}\tag{1}

or

cij=ai1b1j+ai2b2j+ai3b3j++aikbkj.c_{ij}=a_{i 1} b_{1 j}+a_{i 2} b_{2 j}+a_{i 3} b_{3 j}+\cdots+a_{i k} b_{k j}.

Is the matrix product commutative?

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