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In a study designed to investigate the effects of a strong magnetic field on the early development of mice, ten cages, each containing three 30-day-old albino female mice, were subjected for a period of 12 days to a magnetic field having an average strength of 80 Oe/cm. Thirty other mice, housed in ten similar cages, were not put in the magnetic field and served as controls. Listed in the table are the weight gains, in grams, for each of the twenty sets of mice.

 In Magnetic Field  Not in Magnetic Field \scriptstyle \begin{array}{c} \hline \text { In Magnetic Field } & \text { Not in Magnetic Field } \\ \hline\end{array}

 Cage  Weight Gain (g)  Cage  Weight Gain (g) 122.81123.5210.21231.0320.81319.5427.01426.2519.21526.569.01625.2714.21724.5819.81823.8914.51927.81014.82022.0\scriptstyle\begin{array}{cccc} \text { Cage } & \text { Weight Gain (g) } & \text { Cage } & \text { Weight Gain (g) } \\ \hline 1 & 22.8 & 11 & 23.5 \\ 2 & 10.2 & 12 & 31.0 \\ 3 & 20.8 & 13 & 19.5 \\ 4 & 27.0 & 14 & 26.2 \\ 5 & 19.2 & 15 & 26.5 \\ 6 & 9.0 & 16 & 25.2 \\ 7 & 14.2 & 17 & 24.5 \\ 8 & 19.8 & 18 & 23.8 \\ 9 & 14.5 & 19 & 27.8 \\ 10 & 14.8 & 20 & 22.0 \\ \hline \end{array}

Test whether the variances of the two sets of weight gains are significantly different. Let α=0.05.\alpha=0.05 . For the mice in the magnetic field, sX=5.67;s_{X}=5.67 ; for the other mice, sY=3.18s_{Y}=3.18.

Question

Find the relative rate of change of f(x) at the indicated value of x. Round to three decimal places. f(x)=420-5 x; x=25

Solution

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Answered 2 years ago
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To find the relative rate of change of a function f(x)f(x) we use the formula: f(x)f(x)\frac{f'(x)}{f(x)}. We need to find the logarithmic derivative f(x):

ddxlnf(x)=54205x\frac{d}{dx}\ln f(x)=\frac{-5}{420-5x}

By substituting x=25x=25 we get:

ddxlnf(25)=0,017\frac{d}{dx}\ln f(25)=-0,017

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