## Related questions with answers

Question

Find the standard equation of the sphere. Center: (-3, 2, 4), tangent to the yz-plane

Solutions

VerifiedSolution A

Solution B

Answered 2 years ago

Step 1

1 of 4Given data: Center: $\left(-3,2,4\right)$

Step 1

1 of 2If sphere is tangent to yz-plane then sphere has a point with $x=0$ and vector from the Center of the sphere to this point is perpendicular to the yz-plane, i.e this point has coordinats $(0,2,4)$

Find Radiuis:

$R=\sqrt{3^2 + 0^2 = 0^2} =3$

Use the standart equation of a sphere $(x-x_0)^2 + (y-y_0)^2 + (z-z_0)^2 = R^2$

$(x+3)^2 + (y-2)^2 + (z-4)^2 = 9$

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Create an account to view solutions

By signing up, you accept Quizlet's Terms of Service and Privacy Policy

## Recommended textbook solutions

#### Thomas' Calculus

14th Edition•ISBN: 9780134438986 (5 more)Christopher E Heil, Joel R. Hass, Maurice D. Weir10,144 solutions

#### Calculus: Early Transcendentals

8th Edition•ISBN: 9781285741550 (5 more)James Stewart11,085 solutions

#### Calculus: Early Transcendentals

9th Edition•ISBN: 9781337613927 (2 more)Daniel K. Clegg, James Stewart, Saleem Watson11,050 solutions

## More related questions

1/4

1/7