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Find the standard form of the equation of the hyperbola with the given characteristics. Vertices: (0,4),(0,0)(0, 4), (0, 0); passes through the point (5,1)(\sqrt{5},-1)

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Answered 2 years ago
Answered 2 years ago
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Vertices:

(0,4),(0,0)(0,4),(0,0)

and it passes through the point

(5,1)\left(\sqrt{5},-1\right)


the transverse axis of the hyperbola is vertical and the center is :(0,2)(0,2) and a=2a=2

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