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Find the sum of the series. 3+9/2!+27/3!+81/4!+. . .

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3+92!+273!+814!+=311!+322!+333!+344!+=n=13nn!3 + \dfrac{9}{2!} + \dfrac{27}{3!} + \dfrac{81}{4!} + \cdots =\dfrac{3^1}{1!} + \dfrac{3^2}{2!} + \dfrac{3^3}{3!} + \dfrac{3^4}{4!} + \cdots = \sum_{n=1}^{\infty} \dfrac{3^n}{n!}

First we write the series as a summation.

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