Question

Find the transpose of

A=[103214].A=\left[\begin{array}{rrr} -1 & 0 & 3 \\ 2 & 1 & -4 \end{array}\right].

Solution

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Given that

A=[103214]A = \left[ \begin{array}{ccc} -1 & 0 & 3\\ 2 & 1 & -4 \end{array}\right]

. To find the tranpose of AA which is denoted by AA', we need to interchange rows and columns of AA. Interchanging rows and columns of AA gives us

A=[120134]A' = \left[ \begin{array}{cc} -1 & 2\\ 0 & 1\\ 3 & -4 \end{array}\right]

.

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