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Question

# Find the vectors whose lengths and directions are given. Try to do the calculations without writing.Length $\quad \quad$Direction(d). $a>0 \quad \frac{1}{\sqrt{2}} \mathbf{i}+\frac{1}{\sqrt{3}} \mathbf{j}-\frac{1}{\sqrt{6}} \mathbf{k}$

Solution

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Step 1
1 of 2

Part D:

Multiply the scalar length by the unit vector direction to find the actual vector.

$a\left(\dfrac{1}{\sqrt{2}}\mathbf i+\dfrac{1}{\sqrt{3}}\mathbf j -\dfrac{1}{\sqrt{6}}\mathbf k\right) =\dfrac{a}{\sqrt{2}}\mathbf i+\dfrac{a}{\sqrt{3}}\mathbf j -\dfrac{a}{\sqrt{6}}\mathbf k$

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