Question

Find the velocity of the aerosol solid particles when t=10 μst=10\ \mu \mathrm{s}, if when t=0t=0 they leave the can with a horizontal velocity of 30 m/s30 \mathrm{~m} / \mathrm{s}. Assume the average diameter of the particles is 0.4 μm0.4\ \mu \mathrm{m} and each has a mass of 0.4(1012)g0.4\left(10^{-12}\right) \mathrm{g}. The air is at 20C20^{\circ} \mathrm{C}. Neglect the vertical component of the velocity. Note: The volume of a sphere is t=43πr3t=\frac{4}{3} \pi r^3.

Solution

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Given:

  • The velocity at t=0st=0\,\text{s}: U1=30msU_1 = 30\,\frac{\text{m}}{\text{s}}
  • Final time: t=10×106st = 10\times10^{-6}\,\text{s}
  • Diameter: D=0.4×106mD = 0.4\times10^{-6}\,\text{m}
  • Mass: m=0.4×1012g=0.4×1015kgm = 0.4\times 10^{-12}\,\text{g} = 0.4\times 10^{-15}\,\text{kg}
  • Density of air: ρ=1.202kgm3\rho = 1.202\,\frac{\text{kg}}{\text{m}^3}
  • Dinamic viscosity of air: μ=18.1×106Nsm2\mu = 18.1\times10^{-6}\,\frac{\text{N}\cdot\text{s}}{\text{m}^2}

Required:

  • The velocity UfU_\text{f} at the final time

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