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Find the vertex and the axis of symmetry of the graph of the function. f(x)=5(x2)2f ( x ) = 5 ( x - 2 ) ^ { 2 }

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We would like to find the vertex and the axis of symmetry of the graph of the function

f(x)=5(x2)2\color{#4257b2}f(x)=5(x-2)^{2}

First, we note that the function f(x)=5(x2)2\color{#4257b2}f(x)=5(x-2)^{2} is on the form f(x)=a(xh)2\color{#4257b2}f(x)=a(x-h)^{2} where a=5\color{#4257b2}a=5 and h=2\color{#4257b2}h=2, so we can use the characteristics of the function f(x)=a(xh)2\color{#4257b2}f(x)=a(x-h)^{2} to find the vertex and the axis of symmetry of the graph of f(x)\color{#4257b2}f(x).

Since we know that in the function f(x)=a(xh)2\color{#4257b2}f(x)=a(x-h)^{2} the vertex is (h, 0)\color{#4257b2}(h,\ 0), so the vertex of the graph of f(x)=5(x2)2\color{#4257b2}f(x)=5(x-2)^{2} is (2, 0)\color{#c34632}(2,\ 0).

Also in the function f(x)=a(xh)2\color{#4257b2}f(x)=a(x-h)^{2} we know that the axis of symmetry is x=h\color{#4257b2}x=h, so the axis of symmetry of the graph of f(x)=5(x2)2\color{#4257b2}f(x)=5(x-2)^{2} is x=2\color{#c34632}x=2.

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