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Find the vertex, the yy-intercept, and symmetric point, and use these to sketch the graph.
y=8x2+40x+37y=8 x^2+40 x+37

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Answered 1 year ago
Answered 1 year ago
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To find the vertex, transform the equation to y=a(xh)2+ky=a(x-h)^2+k in which vertex has the coordinates V(h,k)V(h,k). First complete the square.

y=(8x2+40x)+37=8(x2+5x+254)8254+37=8(x+52)213=8(x+52)213\begin{aligned} y&= (8x^2+40x)+37\\\\&=8\bigg(x^2+5x+\dfrac{25}{4}\bigg)-8\cdot\dfrac{25}{4}+37\\ \\&=8\bigg(x+\dfrac{5}{2}\bigg)^2-13\\\\&=8\bigg(x+\dfrac{5}{2}\bigg)^2-13 \end{aligned}

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