## Related questions with answers

Question

Find $y^{\prime}$.

y=ln sec x

Solution

VerifiedAnswered 2 years ago

Answered 2 years ago

Step 1

1 of 2Differentiate $y$ with respect to $x$ by applying the Chain Rule to solve for $y'$

$\begin{align*} y'&=\dfrac{d}{dx}(\ln \sec x) \\ &=\dfrac{1}{\sec x}\cdot\dfrac{d}{dx}(\sec x) \\ &=\dfrac{1}{\sec x}\cdot\sec x\tan x \\ &=\tan x \end{align*}$

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