Question

Find yy^{\prime}.

y=ln sec x

Solution

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Answered 2 years ago
Answered 2 years ago
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Differentiate yy with respect to xx by applying the Chain Rule to solve for yy'

y=ddx(lnsecx)=1secxddx(secx)=1secxsecxtanx=tanx\begin{align*} y'&=\dfrac{d}{dx}(\ln \sec x) \\ &=\dfrac{1}{\sec x}\cdot\dfrac{d}{dx}(\sec x) \\ &=\dfrac{1}{\sec x}\cdot\sec x\tan x \\ &=\tan x \end{align*}

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